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Started January 30th, 2008 · 19 replies · Latest reply by plagasul 13 years, 1 month ago
so, here's an absurd one.
make a song of exactly 2 minutes, 43 seconds and 96.9098 milliseconds that uses frog and rain sounds only.
post the song on ccmixter and post a link to it here, make sure the description of the song makes no sense at all.
the weirder the song the better.
for extra bonus points figure out why the song needs to be exactly that long and explain it's relation to the imaginary number i.
- bram
Is it the average length of sounds on here?
Google translated it to 2.71828183 minutes but googling that gets dangerous.
It's apparently e constant. http://en.wikipedia.org/wiki/E_(mathematical_constant)
and i am doing this dare. now. be ready!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Count me in, is there a deadline for this ?????
When you say rain does that exclude thunder ???
exp(1) = 2.718282 which equates to the 2 min 43seconds and 96.9098 milliseconds
exp(i1) = sin(1) + icos(1) this then gives the following cartesian coordinates
exp(i1) = 0.841471 + i 0.540302
I think i may be the number of grains of salt haarvested from ye dead sea & it may take ye 2 minutes, 43 seconds and 96.9098 t'grab that thar salt, afore ye is chased outa the sea by me
haha, avahst Jim lad
Sounds awesome!
I agree with the question above, Are "tunder" sounds allowed?
and we are not limited to 2 sounds right? (just Rain and Frogs, any number of samples may be used )
7,824,097 are the closed number of samples i can get to (pro tools 8 LE)
I guess I'm first
http://ccmixter.org/files/miniPhil/29265
I know it says 2:44 but it's really 2:43:93. That was as close as I could get.
miniPhil
I guess I'm first
http://ccmixter.org/files/miniPhil/29265I know it says 2:44 but it's really 2:43:93. That was as close as I could get.
That was a very nice way to spend 2:43 I like it. Good work.
Sample rate is counted "per second". 44.1kHz means 44100 samples per 1 second.
So, let see, what kind of sample rate we need. First - let create a math.
SR / 1s = x / t
where
SR = samplerate
1s = 1 second
x = our variable
t = less than 1 second ending (96.9098ms /1000 = 0.0969098s)
x / t must be a total number.
(0.0969098 * 10 000 000) / 0.0969098 = 1
Then SR = 10 000kHz = 10MHz
But both - SR and the number 969098 can be divided by common numbers, so we can decrease the SR a little bit.
/2
5000 kHz
484 549
and there are no more common numbers to divide (SR can be divided only by 2s and 5s, none supported by variable x)
So you need the SR to be 5MHz in order to achieve such digital accuracy. Such samplerate - 5MHz - is not usual for sound, even not for ultrasound. Our systems use 192kHz resolution (it's 0.192MHz). Hypersound I guess would be... But Cool Edit (aka Adobe Audition) can and will produce sound sample at that sample rate.
(-;
...and now a little bit of fun. if we divide 5000 kHz / 192 kHz - we get 26.
Why 26 or what to do with that? If we resample sound frequency, dividing it by 2 by 2 by 2 by 2 by 2 (5 octaves down but perhaps 4 should be enough), then we could probably emulate frogs with crickets (some species work sound similar to frogs when are 3 octaves down), and thus - we achive what we wanted to. Sound taken from it's natural environment (5MHz) and put into standard 192kHz as something that we wish to sell as "frogs". (-;
With rain, we should try to capture very small drops in order to resample it later. Drizzle perhaps? Or water bobbles in coca cola (-;
The relation to imaginary number "i" is obvious, so there is no need to explain. (-;
miniPhil
I guess I'm first
http://ccmixter.org/files/miniPhil/29265I know it says 2:44 but it's really 2:43:93. That was as close as I could get.
I guess you won the prize. Dammit! Dammit! Dammit! Dammit! Dammit! Dammit! Dammit! Dammit! Dammit! Dammit! Dammit! Dammit!